2x^2-33x+8=0

Solution for 2x^2-33x+8=0 equation:

2x^2-33x+8=0

a = 2; b = -33; c = +8;
Δ = b2-4ac
Δ = -332-4·2·8
Δ = 1025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1025}=\sqrt{25*41}=\sqrt{25}*\sqrt{41}=5\sqrt{41}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-33)-5\sqrt{41}}{2*2}=\frac{33-5\sqrt{41}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-33)+5\sqrt{41}}{2*2}=\frac{33+5\sqrt{41}}{4}
$